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How to assignment an array with a define type at run time?

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drzsmith

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I have strings data that I load in to array at compile time.

Code C - [expand]
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char array1[] =  ("xxxxx1");
char array2[] = ("xxxxx2");
char array3[] = ("xxxxx3");


I would rather load the values at run time(below)
is this possible?


Code C - [expand]
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#define str1 xxxx1
#define str2 xxxx2
#define str3 xxxx3
 
main(){
 
 char array[10];
 
//wrong. 
 array = str1;
 
}


thans drz
 
Last edited by a moderator:

You can do some pointer array hacking; e.g.

Code C - [expand]
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char *str="1234567890";
 
main()
{
  char *ptr;
  char y;
...
...
  y = ptr[2];
}


Might be dependent on the compiler and it's optimizations. Also, poorly optimized code would ruin the day - about 20 time slower in some case. Carefully consider reading the assembly code (provided it compiles :)).
 
Last edited by a moderator:

drzsmith said:
I have strings data that I load in to array at compile time.

char array1[] = ("xxxxx1");
char array2[] = ("xxxxx2");
char array3[] = ("xxxxx3");

I would rather load the values at run time(below)
is this possible?


#define str1 xxxx1
#define str2 xxxx2
#define str3 xxxx3

main(){

char array[10];

//wrong.
array = str1;

}

thans drz
Click to expand...

Can you explain little more what you actually want to do?
 

drzsmith said:
I would rather load the values at run time(below) is this possible?


Code C - [expand]
1
2
3
4
5
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8
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10
11
12

#define str1 xxxx1
#define str2 xxxx2
#define str3 xxxx3
 
main(){
 
 char array[10];
 
//wrong. 
 array = str1;
 
}


thans drz
Click to expand...

"array" being a char array name, it holds the starting address of the array in the memory. If you try to assign a new address to this pointer during run time (try to destroy the array's existance), there will be compiler error. L-value required will be shown by the compiler
 

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