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[SOLVED] Low voltage lock out circuit

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ful24

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hi, i am building a small inverter project, which the tutor asked to put a Low Voltage Lock Out circuit to prevent the battery being drained out. i have designed a circuit which contains a comparator, voltage reference, voltage divider, and MOSFET( switch ), to disconnect the battery when the voltage is lower than the reference. Is there any simpler circuit or ideas for this LVLO circuit? any disadvantages about the one i designed?
thanks.
 

Use a TL431A with a bleeder resistor .The opto at the cathode is switching at the gate of the MOSFET .ON LVcut posn. the 431 cuts off and switches the Mosfet .
 
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    ful24

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thanks for the reply. Vimalkhanna

are you saying by using the TL431A with a bleed resistor, i dont need a comparator to switch the MOSFET, by the way the MOSFET im using is a P-Channel MOSFET.
 

That is correct .
The 431 is a comparator with gate ref at 2.5VDC
Any bleeder voltage at 2.51V switches ON the cathodes and you can use this for switching your mosfets .
I have used this regularly for 10.8VDC LV battery discharge cutoff .
 
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thank you very much. thats what im gonna use.
 

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