HELP INCREASING CURRENT CAPACITY OF OP AMP (LM124 LM324)

hI,
I need help with what should be relatively simple problem. I have attached the circuit so far .
Basically I have a circuit that is summing two voltages. This part of the circuit works.
i then wanted to increase the output current capacity of the circuit to drive a larger load then what the LM124 or LM324 chip can handle.
So I added a TIP110 transistor to provide more current capacity and this sort of works. It follows the voltage and does provide more current capacity, however, when the output voltage is lower, under 10v the transistor heats up extremely quiock. Is there any other way to increase current capacity of the LM124 op amp so it can handle a continuous 1amp. (most likely current in real operation wil be 500mA but I want to have clearance in case future increase is required. Preferably I would want it to handle 500mA withpout to much temperature rise.

The current setup works ok when the output voltage is higher, closer to 22v but still gets warm. I have heat sink for now to dissappate the heat but it'll heat up enclosure that it is mountwed in..
Any help would be great

The power dissipation of a linear amplifier is simply (Vin-Vout)*Iout, it doesn't depend on the circuit details.
Heatsink is the only option, if you don't go for a PWM circuit.

A PWM circuit involves an output filter, switching noise, and a much more complex circuit. In some cases, an integrated buck converter,
e.g. National Simple Switcher may serve the purpose. But a detailed specification would be needed to design a switcher circuit.

You made a class-A room heater.
Audio amplifiers use class-AB so they don't get so hot.

Audio amplifiers use class-AB so they don't get so hot.

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For an one-quadrant linear amplifier, there's no difference between class A and class AB. The transistor current is exclusively flowing into the load.

So using mosfet instead of BJT would not help the situation?? sorry if thats a silly question but im only new to this and just getting my head around the basics still.

skyline79 said:

So using mosfet instead of BJT would not help the situation?? sorry if thats a silly question but im only new to this and just getting my head around the basics still.

Click to expand...

The power in a resistor or transistor makes heat. Power is the voltage across it (input to output) times the current through it. If it is linear then it gets hot. If it is quickly switching on and off then it does not get hot.

The total current in one transistor can be distributed , by making a parallel connection of transistor , but do keep in mind that the transistor should be matching .

Most of the power transistor comes with 1W of continous power dissipation, so by using a switching circuit you can reduce the average power dissipation much below the defind limit

Added after 29 seconds:


The total current in one transistor can be distributed , by making a parallel connection of transistor , but do keep in mind that the transistor should be matching .

Most of the power transistor comes with 1W of continous power dissipation, so by using a switching circuit you can reduce the average power dissipation much below the defind limit