radius2
Newbie level 6
Hi
I was reading chapter 12 page 836 in Gray Hurst Lewis and Meyer book.
In figure 12.24a the DM half-circuit for the fully differential opamp on the
previous page is drawn. The input signal is -vid / 2 and the output signal is
vod / 2 which means that the half circuit is inverting. However, my opinion is
that the half circuit in fig. 12.24a cannot be inverting. The first common
source stage inverts and the second inverts back which results in a noninverting
operation. I understand that the fully differential amplifier (from vid to vod) is inverting but not why the half circuit in fig. 12.24a is.
Does anybody have an idea or am I missing something?
Thanks
I was reading chapter 12 page 836 in Gray Hurst Lewis and Meyer book.
In figure 12.24a the DM half-circuit for the fully differential opamp on the
previous page is drawn. The input signal is -vid / 2 and the output signal is
vod / 2 which means that the half circuit is inverting. However, my opinion is
that the half circuit in fig. 12.24a cannot be inverting. The first common
source stage inverts and the second inverts back which results in a noninverting
operation. I understand that the fully differential amplifier (from vid to vod) is inverting but not why the half circuit in fig. 12.24a is.
Does anybody have an idea or am I missing something?
Thanks