CC1000 impedance matching (beginner)

I have a design using CC1000 RF chip for transmitting telemetry data on 433 MHz. For the range I require the project includes a low power amplifier to reach ~100 mW.

The output impedance of the CC1000 is 140Ω according to the datasheet. Calculating a normal impedance matching circuit I would connect the components to GND. The TI recommended circuit for impedance matching connects the inductor and the capacitor to Vcc. On the other side the RF amplifier recommended circuit has a 180Ω resistor connected to GND.

In my limited experience I never saw impedance matching components connected to Vcc. So I see two possible solutions:
1. Connect the 180Ω resistor to Vcc and the RF signal will be referenced to the Vcc pin. But in my opinion that would mean that I should connect the antenna GND to VCC.
2.Calculate the components for the CC1000 matching as referenced to the GND.

In my limited experience I never saw impedance matching components connected to Vcc.

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Very simple. It's a LC tank circuit that must be connected to VCC to supply the PA. VCC, particularly the CC1000 pins, need a low impedance decoupling to GND anyway. But of course, the tank circuit injects additional interference current to VCC. You would however inject much more AC current, if you connect the inductor to VCC and the parallel capacitor to GND. The purpose of the tank circuit is to save an additional inductor respectively choke.

2.Calculate the components for the CC1000 matching as referenced to the GND

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Yes, exactly.