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Why number of used channels in OFDM is not 2^k

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rfsystem

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Please not the textbook answer (my FFT is 2^k (hardware reason) so because of guard bands it could be only a compact subset less than 2^k but greater than 2^(k-1))!


I have found that there exists good preamble symbols for 2^k used carriers which have very low peak to average. Also binary channel subdivision for OFDMA is easier and adaptivity in terms of rates is natural.


Ok, you can say that I need a FFT based guard band but most implementation using oversampling anyway for both RX and TX.

So why not 2^k?
 

i need the answere
 

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