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what is the taylor series expansion of this ?

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what is the taylor series expansion of this ?

1 ÷ (1+(wb)²)
 

which one is the indep. variable, w or b?
 

if b is the indep. variable and w is const.,

1/(1+(wb)2) = 1/(1+(wδ)2) - {2wδ/(1+(wδ)2 )-2}(b-δ) - ........ + …..

see the attachment for further...
 

pmonon said:
if b is the indep. variable and w is const.,

1/(1+(wb)2) = 1/(1+(wδ)2) - {2wδ/(1+(wδ)2 )-2}(b-δ) - ........ + …..

see the attachment for further...
Click to expand...

thank u my friend but i have the result but i dont know the solution .........the question is 9.th in pdf file
 

ok guys i solved my problem thnk u for all
 

Care to let us in on the solution?
 

E-design said:
Care to let us in on the solution?
Click to expand...

sure the taylor expansion of 1/1+x² = Σ ((-1)^n ) (x^2*n) n=0:finite wb=a in the question ....sorry e desing i didnt tell u wb is a constant at the first post...thank u for all your helps
 

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