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Decimal to Binary Conversion

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I found this C program from internet:-

void d2b(unsigned int x, int *c)
{
int i;
for(i=0;i<=15;i++)
*(c++)=(x>>i) & 0x1;
}

For the bolded line, what does it mean? Can anyone please guide me?
 

c is a pointer to an Array of ints and the number to be converted is in x.
(x >> i) & 0x1; the number is shifted right i times and andded with 1.
*(C++) = the result is assigned to the array and the array index is incremented.
If x = 20, you would end up with
c[] = {0,0,1,0,1}; in the array.
The only purpos I can see for this is to print out the number in binary?
 

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