ruwan2
Member level 5
Hi,
When I read the below description, I can't follow the column manipulation to get (3.5)
When to do the row reverse, we get the two right vectors but without conjugate signs. If we do the column reverse on R5, I think we have to reverse the two vectors again, but it appears not do so on the picture.
The conjugate procedure is on R5's elements and the elements of the two right vectors, is it right?
That is, I can see the column reverse on R5, but I can't see it on the two right vectors. Can you explain it to me?
Thanks,
When I read the below description, I can't follow the column manipulation to get (3.5)
When to do the row reverse, we get the two right vectors but without conjugate signs. If we do the column reverse on R5, I think we have to reverse the two vectors again, but it appears not do so on the picture.
The conjugate procedure is on R5's elements and the elements of the two right vectors, is it right?
That is, I can see the column reverse on R5, but I can't see it on the two right vectors. Can you explain it to me?
Thanks,