Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

bit rate error (BER) Simulations and channel noise

Status
Not open for further replies.

Ata_sa16

Full Member level 6
Joined
Mar 29, 2016
Messages
343
Helped
59
Reputation
118
Reaction score
58
Trophy points
28
Location
Milky Way Galaxy, 179° 56′ 39.4″
Activity points
2,221
Hi,

I wanted to know about these parameters in BER simuation in ADS.

eda2.png

I know Power_dBm it is transmitters output signal power

I know BitsPerSymbol it is 2 since it is QPSK modulation.

I know No_dBm is the noise power

There is a problem here:

EbN0 = 6 (It is swept to find BER)

No_dBm = Eb_dBm - EbN0


So basically we sweep the noise power

but why we have energy per bit here ??

No_dBm = Eb_dBm - EbN0 (It is swept)

Eb_dBm = Power_dBm - 10*log10( SymRate*BitsPerSymbol )


eda3.png
 

I think I understood what is happening in this tutorial. :idea::idea::thumbsup::thumbsup:

Eb = C / R

Eb is energy per bit
C is carrier power
R is bit rate

in this tutorial, it seems Eb is calculated first

Eb_dBm = Power_dBm - 10*log10( SymRate*BitsPerSymbol )

Eb_dBm = Eb is energy per bit
Power_dBm = C is carrier power
10*log10( SymRate*BitsPerSymbol ) = R is bit rate

Here symrate = Bitrate/2 (QPSK) and bitspersymbol=2 so basically 10*log10( Bitrate )

now we want to find channel noise density

we cant write like this: No(noise density)=Eb/(Eb/No)

So
No_dBm = Eb_dBm - EbN0

and we sweep Eb/No from 0 to 10.
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top