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Diode in Series with DC

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RITESH KAKKAR

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Hello,
I am testing diode graph what this mean when there is 12V supply with Diode in series with Resistance?
 

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Hi,

What's your concern?

The negligible couple of microvolts?
Or the microseconds?

--> both have no meaningful influence on a real circuit.

Klaus
 
The output voltage is applied voltage minus the diode drop.
 
That small voltage is possibly an artifact of the simulator.
You are applying DC to the circuit but then simulating in the transient mode when there is no transient source.
What are you trying to determine?
 
Actually, I have readied of diode exponential graph.
 

RITESH KAKKAR said:
Actually, I have readied of diode exponential graph.
Click to expand...
If you want a plot of diode voltage vs. current you can use the .step function to vary a current-source current.
Then using the DC opt point simulation will give you voltage vs. current, as shown below.
I changed the horizontal current axis to exponential (left click on the axis) so the exponential voltage vs. current looks nearly like a straight line.

Diode2.PNG
 
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Hello,
How to do this?
i am getting this
From where you have taken step function ?
 

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RITESH KAKKAR said:
Hello,
How to do this?
i am getting this
From where you have taken step function ?
Click to expand...
Look more closely at my simulation.
There is a .step function directive (SPICE Directive under Edit) which steps the current i in the current source ({i}).
And I did a .op simulation, not a transient simulation as I also showed.

Look up the .step function in the Help file if you don't understand.
 
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