Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
Does it get easier if we assume that the MOSFET is active in it's operation point?
Also (in the first circuit) since there is no current through R1, we can assume that the voltage at the gate is also VDD.
Thank you for expanding the discussion around these tasks. However these circuits are from a task book, and the question of the task is to find an expression for R3 (in the first circuit) and for R4 in the second. I.e. R3 and R4 should be expressed in terms of the other known variables. Do you...
Is this image of yours actually explaining something? Why did you switch places of components? What is R4, where did it come from? Please explain the image. Is it helping answering the problem I'm asking?
I understand the MOSFET is turned on, but how do you mean "R1 should be connected to ground"? There are components between R1 and ground.
Also what do you mean with that "the current in R3 biases the gate-source". The voltage above R3 must be lower than VDD, for there to flow current iD, right?
NMOSFET circuit analysis
I know that there will be no current through R1. The voltage at the source could be expressed as VR3 = R3IDQ, which means that R3=VR3/iDQ. But how can we express VR3 in terms of the known variables?
For a) I understand the actual voltage values vary in amplitude, so when the voltage over C is maximum it will be lower for R and vice versa. But how can you explain this in a mathematical way?
You have a Voltage source of 12 V, three 6V-lamps with 18W and three 6V-lamps with 12W.
How can you connect five of the lamps with the voltage source to make all five have correct power?
I understand that the voltage drop across each lamp must be 6 V, which means that there must be maximum two...
Okay, for the Zener diode of 3.4 V we can say that
* When the voltage is above 0.6 V, it's like a short circuit in the forward direction but an open circuit in the backwards direction.
* When the voltage is between -3.4 up to 0.6V, it's like an open circuit in both directions.
* When the...
1) Why not? Shouldn't the forward biased voltage be in the direction of the diode?
What is keeping the voltage V from being higher than 8 V? If we have a very large voltage source and a small resistance, why wouldn't the voltage be higher?
Can't the forward voltage of the diodes be illustrated as a ideal diode in series with a voltage source with V=0.6?
I.e. like this:
Why is this not correct?
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.
