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that's great john. for your questions, i don't have an exact answer, but you need to get such discrepancies to learn not to trust the simulations! in that world, mesh size plays the key role and you might see even two opposite phenomena by changing it! you need to be always careful about that...
if you post the unit cell image, that would be easier to explain.
For floquet, use sines and cosines to come up with the correct angle of incidence at your BC and source. it is easy. for example, you can set the source as k0*cos(alfa), and then floquet BC needs to be as k0*sin(alfa). this way...
correct! this is because RH and LH are defined based on propagation direction.
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good thoughts!
1- radiation backward +z toward origin means -z!
2- yes.
No, both are wrong! the polarization is a simple topic and that's strange why authors having problem dealing with that...
for characterization of elliptical polarization, you need two parameters: rotation and ellipticity. To find handedness, some info on the phase difference must be provided. I...
disagree! so if you create 2 identical spheres at the same location, first one from metal, and second one from air, u think that the properties of metal is kept at that location?! that's wrong...the order matters.
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I may add, if you have two metals, then what? the rules are...
in the first paragraph of section 7-3-4, last line, says shape and handedness comes from ratio and phase different. So, if it is saying that ratio is used for handedness, it is violating an early statement...I disagree with the book. you might want to read another book that gives you correct...
I am wondering which book you are mentioning?! ellipticity is a ratio of two lengths that leads to some value between 0 and 1. the measure doesn't tell anything about handedness...and we don't have negative length, hence no negative ellipticity.
So, maybe the comsol one is different from HFSS! Do you get the same error in comsol?
for these cases, I can think of two solutions. first is to use equivalent fields and currents in your model. So you need to find the response of cross section of copper and the BC, then add an equivalent...
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