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Re: communications 2
1) data rate in bps = 25*(160*120)*(3*8bits)=11520000 bps
2) baud rate = twice of bandwidth = 2* 44.1 khz = 88.2khz;
bit rate in bps = baud rate * number of bits/sample
= 88.2khz*(2*8)= 705600 bps
3) ambiguous
4) bits required for one sec ( sum of audio and...
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