Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
oversampling data recovery circuit
Increasing the bandwith of the loop, the recoverd clock will track the input noisy clock. but whether the data can be decoder by the recoverd clock?
connect verilog reg to std_logic_vector
p_divide_v_actl_dvdnd[DWIDTH - 1:V2V_i] = p_divide_v_dffrnc[DWIDTH - 1 - V2V_i:0];
I think you should use a decode for all the bits of p_divide_v_actl_dcdnd to select to connect each bit of p_divide_v_diffrnc.
Ryan
scanning:stdin dc
I have install syn2005 in RedHat AS 4.0.
when I start DC use this command dc_shell. It gives me the following message,
and begain for waiting, I don't now why.
Synopsys Tcl Syntax Checker -Version 1.0
Loading snps_tcl.pcx...
Loading syn.pcx...
scanning:stdin
Anyone know...
Maybe you should define another 4 signals LED_0,LED_1,LED_2,LED_3 like this:
signal LED_0:std_logic;
signal LED_1:std_logic;
signal LED_2:std_logic;
signal LED_3:std_logic;
then use these 4 signals to do port map.
Ryan
CMOS
Your question is not very clearly.Maybe your meaning is that the buck (or body) of nMOS connect to Vdd and the buck of pMOS connect to GND. what will happen?
The buck of nMOS is P type, the source and the drain of the nMOS is N type, generally we connect the buck to GND, and the source...
when a CMOS inverter in transition mode, if the voltage of input signal changes very small, the output signal will change from high to low or low to high. So the gain of CMOS inverter in transition mode is very hight.
Ryan
hspice vco gain
in PLL project design, Kvco is not linear. sometimes it is OK, if the curve of Kvco is monotone.
In the considering of system stability, you should check when using the max Kvco and min Kvco, the PLL system should be both stable.
Ryan
crystal lqz
I think one of the capacitor are used for phase shift. the very large resistor in parallel is used to set the bias of the inverter, and keeps it in amplifer condition.
The circuit of QZP100K and QZS100K maybe it's the same. From the subcircuit, we can see the node and the parameter...
To fix your probem, I think you should follow this flow:
First, check when you give a negative clock voltage at P3^3, whether the uC will tirgger the interrupt. if the interrupt is OK, then do the second check. if NOT, check the interrupt register setting, insure the uC will accept and...
It seems that the output of IRQ is drain open, it must connect a pullup resistor. In your code, you set IT1=1, thet means if P3^3 goes from High-to-Low will trigger interrupt.
So I think if IRQ is drain open, if has no interrupt, it is state is High Z, and use a pullup resistor, then output...
This condition refers to dynamic displaying. the display step is like this:
1. for one time, you can select one seven segment, and put your digit to it, then wait for a moment (< 0.1/4 s)
2.and then, you can select another seven segment, and do the same thing as the first one.
3. repeat the...
It seems we should repeat it 300 times for 300 cycles. I think. but I have another solution for your case: I often use a wave display tool - CosmosScope do this work. there are many function in CosmosScope that can measure different parameters.
Ryan
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.
