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sorry for my mistake,i didnt know about that,thank you for correcting...
so the best way is to use a chip derived 8051 with USB like PIC18F2455...
also i have a doubt that is, any 8051 development kit can be used to develop anyother companies 8051 derived IC??
also which is a good 8051 kit...
Hello there,
*My simple objective is to send some codes from my PC to a Micro-controller,which will then take decision based on the received code and control another Machine
So my idea is,all PC comes with a 8-bit lan port,so what if i could connect the 8 bit LAN wires to one of the port of...
I already built the Mic amp yesterday and its working fine with my transmitter.... :)
I used BC547,instead of BC549C...
it has less gain than the orginal circuit coz i didnt have BC549C which has 500 beta, BC547,has beta of around 200.. so less gain..
I didnt use the 10K pot...
I connected...
I think the R1 can be increase to 162K and R2 to 22K... with it the Zin will increase to 1.3K
The Zout is 1.5K when the pot is set to half that is 5K,2.2K||5K = 1.5K
From other source , i came to know this thing about Cin and Cout
Why is that the Cin and Cout Reactance of the lowest...
Thanks for the reply...
i calculated the Input impedance of this circuit it and its has around 900 ohms
Ic=3mA
Rin=4K
Zin=4K||22K||2.7K||2.2K = 900 Ohms
the Electret mic i have has impedance of 2K ohms...
i think the mic amplifier should have higher impedance than the mic.. am i...
My another simple yet frustrating problem of mine,plz help
1)as the circuit show by Sky_123,i think the Output impedance is 2.2K(Rc),can it be connected to a LM386 AMp Ic which has Rin of 50K ?
2)and it has Input impedance of around 1K, can a Electret mic with 2K ohm impedance be connected to...
hi...i have a simple doubt with Electret mic... i want to make a little microphone amplifier.. but i have a small doubt...
In the below simple circuit,the mic is connected to 9V Dc through a 10K resistor.. so 9/10K=0.0009A..
1)Should the Mic be powered in order to work or not??
2)With 10K...
@varun
Thanks for explaining,i think i understood something
in the above circuit the first stage Zout=R3||Rload(where Rload = next stage input impedance)?
am i right??
or first stage Zout =Rc; as Rc is at one end of capacitor and Rload(i.e next stage input impedance)is on the other side of...
i think Cout is used to block DC from a amplifier stage from passing to another stage and interfering with its bias point..
and it is also used as high pass filter to attenuate signals which are less than cut off frequency...
So the output impedance of a common emitter = Rc||Rload... and the...
For example,if im going to hook up that circuit output to next stage and that stage has 12K input impedance,then (Rload=Rc||RL) = 6K||12K(next stage input impedance) = 4K ohms output impedance
then i could calculate the Cout using the 4K ZOut value???
or as LvW said, to calculate Cout, its...
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