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ekg circuit
The body´s displacement current flows not to ground but rather to the op-amp output circuit.This reduces the pickup as far the ECG amplifier is concerned and effectively the patient.
What body´s displacement current is that ?????
ecg amplifier circuit
Jhon G.Webster, libro: “Médical Instrumentation Applications and
Design”,Pág. 256,257, 258.
Why this negative feedback drives the common-mode voltage to a low value??
problem with 4538
I want to simulate 4538 with Proteus but I can´t.
pin 1=ground
pin2 = resistor(200kohmios) to +5
between pin 1 and pin2 a capacitor (1uF)
pin3= +5
pin4 = wave square
pin5= pin7
pin 6 = out
What happen??
Thanks
Re: feedback techniques
In Mosfet:
When I meassure the output impedance using the convencional way,
Vx/ix= RE +ro(1 + gmRE(1+Ad))= 60Gohmios
If I use feedback techniques to calculate the output impedance,
I have to calculate zoA,
and Zof= zoA(1 + A*f)
A=Io/Vi=gmAd/1+gm*RE+RE/ro =2.47...
biopotencial
I am working with a differencial biopotencial amplifier based on two coupled buffers and a common instrumentation amplifier.
Why must be ac-coupled the bipotential amplifiers??
Thanks
Re: feedback techniques
Hello everybody.
If transistor is a Mosfet.
When I meassure the output impedance using the convencional way, that is, using a voltage source
at the output while shortcutting the dependences ones I get 60 GOhmns. If
I use feedback techniques to calculate the output...
feedback techniques
Hello everybody. I would like ask you for a curious phenomemnon by
measuring
the output impedance in a circuit. Take a look to this
(www.eurobotics.org/vco/circuito.doc) simple circuit. When I meassure
the
output impedance using the convencional way, that is, using a...
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