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Hello
I am designing a precision stop watch with 1 msec precision. I had tried stop watch with 1 msec timer and interrupt.I have checked and upto 1 minute i get exact delay with an error of 100-200 msec and as time passes error increases and after 5 minutes an error of 1 to 5 second is there...
Hello
I wants to implement Autotuning of PID Algo in PIC16 Microcontroller to control temperature.
Most commonly used ziegler method is clear to me with Ultimate Gain and Period Oscillations.
But i want to know how to implement these graphs in C Code. I found somewhere that autotuning...
Hello
I have tested the circuit by setting charging 13.8 Volt and seems battery takes approx 15 hours to fully charged from 10.8 Volt. At 10.8 Volt the charging current is 400mA.
then i increased the charging voltage to 14.5 Volt with current 700mA along with cutoff at 13.8 Volt, then battery...
Actually i want to maximize the life of battery with charging circuit.
If circuit posted by Rainer works well for Lead Acid Battery, then there is no need to go for Circuit with Micro controller. And if there is any drawback with this circuit then i will go for PIC.
If circuit by Rainer works...
that is the concept which i am searching for. thanks for you post.
if lead acid battery charging should follow 3 state charging, but i think circuit posted by Rainer also follows 3 state charging (initially current 700ma then decreases and then becomes zero.
What will be the benefit in terms...
Thanks for your reply.
As you said Lead Acid Battery Charging should be Voltage and Current Controller but above circuit posted by Rainer is only current controlled, voltage remains constant.
I am fine with programming of PIC. Please posted some circuit for multistage charging.
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I tried this just to know the time taken to charge battery from low voltage (in rare case due to some reason if Vbat goes below 8 Volt).
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I want to confirm whether i need to increase current from 400mA to 700mA at charging of 10.8 Volts
Here i am attaching my requirement.
a) When AC is present Comparator 1 detects it and feed the signal to relay so that relay gets off.
b) When AC is not there, and Vbat >10.8 comparator 2 detects it and feed the signal to Activate it. Once relay Activate, battery voltage goes to load.
c) When...
Relay switching corresponds to 10.8 Volt is clear to me but if AC mains is present i want AC (converting into DC) goes to load and if AC not present then in that case circuit first check Voltage corresponds to 10.8 Volt. If voltage > 10.8 Volt, it switches the Relay else not.
I am planning to...
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