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Hi Barry
I tried this out with a small relay and I get the same. If you look at the scope pic in the first post you get this before the switch bounce starts. I also had this on mine, on the initial switch on pulse. Also if he is measuring from the top of the coil, how do you get a positive...
Yes the capacitor may fix the problem. But the OP asked what was causing this. The cause is probably as I mentioned in my last post the inrush current of the coil and externals inductances. When you first connect the power to the circuit the power supply will see a very small inductance in...
If this is being measured on the D.C power line then it looks like overshoot possibly caused by relay inrush current and supply line inductance. but as you haven't supplied any circuit diagram or pictures of your setup I can only suggest this as an observation.
Thanks
Adam
I call these box headers and sockets. The one on the right is a two wall version. I don't know the manufacturer, sorry. See if you can see a symbol of some kind on them.
Adam
You have a D.C source which maintains a fixed potential difference between its two terminals. Because the output is taken from the lower potential side of the battery then this point will always be 3 Volts lower than the positive potential terminal of the battery. So when your sine wave (we will...
My company uses thousands of crimped connections every year and if done correctly they are much better than soldering. The soldering after can damage the PVC insulation of the wire and reduce the ability for the outer claps to hold the wire properly. When you solder a wire some of the solder...
Yes I agree, we need to know what the output of the sensor is. For this to work this won't the output of the sensor need to be able to go negative as it's common point is now 2.5 Volts. Also I would buffer the reference voltage for this use as I suspect the pressure sensor may draw several mA's...
Hello Audioguru.
I don't know what sensor is being used but I guess he wants to trigger when a certain pressure has been reached. If you connect the common of the sensor to the reference pin then won't the output be high all the time as the sensor is not likely to have a zero output is it? Then...
Just because it's modulated doesn't mean it's A.C. If the output voltage doesn't go negative or the current doesn't change direction then it's not A.C. The reason I ask is that the regulation LVD asks what the voltage is because AC is expressed in RMS. But for you your lucky you are 15 Volts...
Shouldn't there be another resistor on the + input? I think the capacitor in this case will function as a speed up capacitor charging and discharging the internal capacitance of the op-amps + input thus increasing the switching times.
Adam
Hello
Looking at the spec of this op-amp, you really need to look at using a comparator or the circuit Sunnyguy drew for you. Even when you have the input pins within the limits of the device you still have to consider input signal level, slew rate and GBP etc. The device you have chosen is a...
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