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how do the exponent algorithm implement in verilog?
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ASIC Design Methodologies & Tools (Digital)
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openwindows
Joined: 18 Jan 2002
Posts: 38
23 Mar 2003 4:00
how do the exponent algorithm implement in verilog?
1:
(1-2^-n)
2:
(1-2^-n)^6
3:
(1-2^-n)^1/4
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