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lhasayak
Joined: 18 May 2007 Posts: 10
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12 Feb 2009 3:26 In HFSS, why ports need to far away from discontinuity? |
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| I know it is for high order modes to die out before they reach ports. If they are real, why not include them in sim? Thanks.
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wandering heart
Joined: 10 Feb 2006 Posts: 100 Helped: 4
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12 Feb 2009 4:12 In HFSS, why ports need to far away from discontinuity? |
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Physically, the excitation should just be the fundamental mode, since your cable is very long and high-order modes die out. However, in the simulation the port is modelled by a finite surface with the field distribution of the fundamental mode. There will be unwanted modes excited, but they are not physical.
Hope this helps.
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lhasayak
Joined: 18 May 2007 Posts: 10
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12 Feb 2009 7:04 In HFSS, why ports need to far away from discontinuity? |
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| Do you mean ports can excite or accomodate non-physical modes ? is that why transmissio line to DUT should be long enough? Thanks.
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wandering heart
Joined: 10 Feb 2006 Posts: 100 Helped: 4
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12 Feb 2009 11:12 In HFSS, why ports need to far away from discontinuity? |
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| Yes, these can be caused numerically.
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maxwellian
Joined: 22 Feb 2005 Posts: 129 Helped: 18
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13 Feb 2009 20:16 Re: In HFSS, why ports need to far away from discontinuity? |
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lhasayak:
I think it is so that the stray fields from your discontinuity are not picked up in the field port. This would cause numerical error in the S-parameter extraction.
--Max
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si14
Joined: 27 Sep 2006 Posts: 1061 Helped: 664 Location: North America
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14 Feb 2009 13:55 Re: In HFSS, why ports need to far away from discontinuity? |
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It is a limitation of Wave ports.
But I think you can use Lumped ports anywhere inside the geometry. More explanation:
Wave ports solve actual field distributions for one or more propagating or non-propagating Modes.
Lumped ports excite a simplified, single-mode field excitation assuming a user-supplied Zo for S-parameter referencing.
Limitation of lumped ports:
Lumped ports excite only one mode, and therefore are not appropriate for excitations where modal superposition is expected.
Since impedance is supplied by the user, not computed, no alternate definitions (Zpi, Zpv, Zvi) are supplied.
More information can be studied in the attached file.
good luck!
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maxwellian
Joined: 22 Feb 2005 Posts: 129 Helped: 18
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14 Feb 2009 16:13 Re: In HFSS, why ports need to far away from discontinuity? |
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| Yes, you also have to be careful not to use lumped ports if they could possibly couple to other things near them. Since they are not de-embedded, you should be careful about using them at high frequencies.
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