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santumevce1412
Joined: 08 Jan 2008
Posts: 24
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 04 Oct 2008 16:39 nand gate |
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minimum number of 2i/p nand gate required to implement the following function
Y = AB + CD + EF
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dcreddy1980
Joined: 03 Dec 2004
Posts: 128
Helped: 8
Location: Munich, Germany
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| 04 Oct 2008 20:08 nand gate |
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| I think u need "6" 2i/p nand gates for tha above function
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p_shinde
Joined: 25 Feb 2006
Posts: 293
Helped: 4
Location: tokyo
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| 06 Oct 2008 10:50 Re: nand gate |
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I guess this board is not for textbook related questions!!! no one will do ur assignments here 
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Nir Dahan
Joined: 19 May 2008
Posts: 65
Helped: 6
Location: Munich, Germany
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| 06 Oct 2008 13:48 nand gate |
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here is a more interesting question.
if you can use ANY 2 input gate (also mix between gates) can you do it in less than 6 gates?
ND.
http://asicdigitaldesign.wordpress.com
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viju
Joined: 26 Nov 2006
Posts: 52
Helped: 8
Location: Bangalore
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| 06 Oct 2008 15:57 nand gate |
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this can be implemented by 5 gates.
3 AND gates and 2 OR gates.
As 3 . and 2 + is there in equation
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Nir Dahan
Joined: 19 May 2008
Posts: 65
Helped: 6
Location: Munich, Germany
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ramana459
Joined: 01 Apr 2008
Posts: 20
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| 06 Oct 2008 19:20 Re: nand gate |
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If you want to implement using only 2input nand gates.... total 6 gates are required.
1 for (ab)'
2 for (cd)'
3 for (ef)'
4 for (1,2)'
5 for (4,4)'
6 for (3,5)'
here (ab)' menas ......... a,b inputs are connected to 2input nand gate
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Nir Dahan
Joined: 19 May 2008
Posts: 65
Helped: 6
Location: Munich, Germany
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| 06 Oct 2008 21:33 nand gate |
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you can now develop a formula for this problem.
it is log2 of n dependent...
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lsimeon
Joined: 01 Aug 2008
Posts: 43
Helped: 2
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| 09 Oct 2008 13:51 Re: nand gate |
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here is the nand implementation for this function...
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