| Author |
Message |
nxing
Joined: 10 May 2004 Posts: 446 Helped: 13 Location: China
|
11 Jul 2007 2:19 divider |
|
|
|
|
Hi everybody,
I have a question regarding the divider: say I have a divider working at 2GHz, for some reason, there is another signal is added to this 2GHz, (say 2.1GHz), I am wondering whether or not this divider will divide this 2.1GHz? or can I see a signal of 1.05GHz at the output? what's the reason for that?
Thanks
nxing
|
|
| Back to top |
|
 |
Google AdSense

|
11 Jul 2007 2:19 Ads |
|
|
|
|
|
|
| Back to top |
|
 |
biff44
Joined: 24 Dec 2004 Posts: 1835 Helped: 244 Location: New England, USA
|
11 Jul 2007 6:27 Re: divider |
|
|
|
|
| It has been a while since I did the experiment, but as I recall the divider will lock up only on the signal that is higher power, even by a few dB, and ignore the other signal except to treat it as a high frequency phase modulation on the signal it locked up on.
|
|
| Back to top |
|
 |
nxing
Joined: 10 May 2004 Posts: 446 Helped: 13 Location: China
|
11 Jul 2007 17:57 Re: divider |
|
|
|
|
Hi biff44,
First of all, thanks for your reply and I think you are right. That's what I got from my experiment. However, what I can not understand is that if we have two signal being added up in time domain, will the zero-crossing be changed so that the divider will work at other frequency (somewhere between the two frequency)?
Thanks
nxing
|
|
| Back to top |
|
 |
biff44
Joined: 24 Dec 2004 Posts: 1835 Helped: 244 Location: New England, USA
|
12 Jul 2007 19:37 Re: divider |
|
|
|
|
| It does seem to defy logic, but my experience seems to say no. The divider locks up onto the bigger signal and ignores the smaller one. Obviously, if you were designing a system and had a choice, you would want the desired signal to be tens of db above the spurious input--just to make sure.
|
|
| Back to top |
|
 |
psmon
Joined: 04 Jun 2007 Posts: 173 Helped: 22
|
15 Jul 2007 0:23 divider |
|
|
|
|
| You should see both 1 and 1.05 GHz signals from the spectrum analyzer. How strong are the signals depend on the source and the sensitivity of the divider...
|
|
| Back to top |
|
 |
echo47
Joined: 07 Apr 2002 Posts: 4206 Helped: 566
|
15 Jul 2007 2:14 Re: divider |
|
|
|
|
Here's a MATLAB simulation. Add two sinewaves, 2.0 GHz at 0dB and 2.1 GHz at -3dB, and pass it through a zero-crossing detector (no divide-by-2). The vertical axes are linear.
If I decrease the amplitude of the 2.1 GHz sinewave, the square wave's spectrum cleans up more rapidly.
| Code: |
clear;
N = 32000; % number of points
fs = 400.0; % sample rate
f1 = 2.0; % signal 1 frequency
f2 = 2.1; % signal 2 frequency
a1 = 1.0; % signal 1 amplitude
a2 = 0.7071; % signal 2 amplitude
t = (0 : N-1) / fs;
%
y1 = a1 * sin(2 * pi * f1 * t) + a2 * sin(2 * pi * f2 * t);
subplot(4,1,1); plot(t,y1); xlabel('ns'); xlim([0 20]);
h1 = fftshift(fft(y1));
freq = fs * (-N/2 : N/2-1) / N;
subplot(4,1,2); plot(freq, 2/N*abs(h1)); xlabel('GHz'); xlim([0 5]);
%
y2 = sign(y1);
subplot(4,1,3); plot(t,y2); xlabel('ns'); xlim([0 20]); ylim([-1.5 1.5]);
h2 = fftshift(fft(y2));
subplot(4,1,4); plot(freq, 2/N*abs(h2)); xlabel('GHz'); xlim([0 5]); |
|
|
| Back to top |
|
 |