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simple script

 
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ankit12345



Joined: 27 Dec 2005
Posts: 299
Helped: 5
Location: bangalore,India


Post20 Feb 2007 13:55   simple script

Im new to linux.....
I want to write a shell script .......what i did is........

-------------------------------------
#!/bin/bash
echo "some directory num"
read number
echo "$number"

if [ $number = 1] then
cd /proj/caupaxg/cx_modsim/cx_xmac
else
cd /jhsd/kJSAD/SKJ
fi

pwd
---------------------------------------
if i did source......read command failed...........
if i ran directly using the file name.....cd command failed..........

Spent some time in google.....but failed to find the sol......plzz help me.....
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nafraf



Joined: 02 May 2002
Posts: 66
Helped: 2


Post03 Mar 2007 1:13   Re: simple script

It works for me...
Code:
#!/bin/bash

echo "some directory num"
read number
echo "$number"
                     
if [  $number = 1  ]; then
    cd ~/tmp/dir1
else
    cd ~/tmp/dir2
fi

pwd
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pakitos



Joined: 14 Nov 2005
Posts: 318
Helped: 38


Post05 Mar 2007 14:56   Re: simple script

The thing you are doing is easy and straight forward it should work!!
what is your problem?
what do you want to do?
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synpscrk



Joined: 24 Oct 2004
Posts: 15


Post06 Mar 2007 9:17   Re: simple script

Read some book
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gtm56



Joined: 01 May 2008
Posts: 3


Post01 May 2008 10:52   Re: simple script

Hi all,

I'm having a problem with a simple script i'm trying to create.
I have created a file that has this form:
Code:
     
                 2 xx.xxx.xxx.xx
                 1 xxx.xxx.xxx.xx
                 1 xxx.xxx.xxx.xx

*the ips have been replaced with 'x'

Now i want to detect if any number from the first column is above a certain limit.
The problem is that when i use awk to check the first argument in the line it can't be recognised.This is where i need some help.
After the detection i'll do some actions with the ip that refers to the number that has been detected to be higher than the limit.

thanks.
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meitolake



Joined: 07 Oct 2007
Posts: 143
Helped: 23
Location: China


Post02 May 2008 2:01   simple script

Can you show your code?
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gtm56



Joined: 01 May 2008
Posts: 3


Post03 May 2008 11:41   Re: simple script

Here is what i want to do.
The file is created using the netstat command.The problem is that i want to compare only the first column with the variable limit.
Code:
#!/bin/bash -x

limit=4

netstat -tanp | grep \:80 | awk '{print $5}' | cut -f 1 -d: | sort | uniq -c | sort -nr | head -n 20 > test;

chmod +x test

for i in `cat /home/...../test`
do
if [ $limit -lt $i ] then
 echo found
fi

done
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meitolake



Joined: 07 Oct 2007
Posts: 143
Helped: 23
Location: China


Post04 May 2008 5:09   Re: simple script

I have modified your script.

Code:
#!/bin/bash -x

limit=4

netstat -tanp | grep ':80' | awk '{print $5}' | cut -d: -f1 | sort | \
uniq -c | sort -nr | head -n 20 >/tmp/test$$

chmod +x /tmp/test$$

for i in `cat /tmp/test$$`; do
    if [ $limit -lt $i ]; then
        echo found
    fi
done


Last edited by meitolake on 05 May 2008 3:01; edited 1 time in total
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gtm56



Joined: 01 May 2008
Posts: 3


Post04 May 2008 18:33   Re: simple script

Thanks for the modification.

The problem is that something is wrong with i.
If you try this
Quote:
netstat -tanp | grep ':80' | awk '{print $5}' | cut -d: -f1 | sort | \
uniq -c |sort -nr | head -n 20 | awk '{print $1}'

the first column will be printed.However if i try to check each $i ,something is wrong.
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meitolake



Joined: 07 Oct 2007
Posts: 143
Helped: 23
Location: China


Post05 May 2008 3:03   simple script

Please show the error.
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