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Tracid
Joined: 01 Nov 2006
Posts: 51
Location: Neded, Slovakia
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 09 Feb 2007 17:10 Voltage value at the voltmeter |
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WhatstheU.jpg:Uin and resistance values are known. i have to determine the voltage at the voltmeter. The whatstheUt.jpg is what i thought about. is it the right way? or i have to use Norton,Thevenin or something like these? (Uin can be an ideal source with no inner resistance)
PS: i just wanna know all these answers to my three topics.i am not a student anymore,so its not a homework anyway.  ))
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ep20k
Joined: 17 Sep 2002
Posts: 319
Helped: 15
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09 Feb 2007 17:55 Re: Voltage value at the voltmeter |
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1: U=0V
2: google for Wheatstone bridge
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Tracid
Joined: 01 Nov 2006
Posts: 51
Location: Neded, Slovakia
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09 Feb 2007 18:17 Voltage value at the voltmeter |
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| aha! my logic is so short that i just didnt think i can sum R2+R6 and R1+R5 and this is a wheatstone bridge! But why do you say its 0V? 0V should be when the bridge is adjusted! but when all the resistors have they own value,then the resultant voltage could be different,no? lets say current flows.
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ep20k
Joined: 17 Sep 2002
Posts: 319
Helped: 15
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10 Feb 2007 9:58 Re: Voltage value at the voltmeter |
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| Tracid wrote: |
| But why do you say its 0V? 0V should be when the bridge is adjusted! |
That's right!
What I meant was:
whatstheUt.jpg=0V there is no your power source
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Tracid
Joined: 01 Nov 2006
Posts: 51
Location: Neded, Slovakia
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10 Feb 2007 10:30 Voltage value at the voltmeter |
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| oh sorry that picture (whatstheUt.jpg) is my possible solution(but maybe faulty!!!) . The WhatstheU.jpg is the picture we have to solve!
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ep20k
Joined: 17 Sep 2002
Posts: 319
Helped: 15
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10 Feb 2007 15:18 Re: Voltage value at the voltmeter |
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| Ok, then just google for Wheatstone bridge. There is the answer.
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Tracid
Joined: 01 Nov 2006
Posts: 51
Location: Neded, Slovakia
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12 Feb 2007 18:40 Voltage value at the voltmeter |
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| thanks! so now i know that i have to calculate the voltage drop at those two points(at junction of R3,R4 and at junction of R1+R5,R1+R6). and the voltage value across the v-meter will be their difference. but how do i know that i have to substract first voltage value from the second or the seconds value from the first?i hope you understand! the absolute value will be the same but the polarity will be different if i substract them the opposite way.
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Google
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12 Feb 2007 18:40 Ads |
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ep20k
Joined: 17 Sep 2002
Posts: 319
Helped: 15
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02 Mar 2007 17:20 Re: Voltage value at the voltmeter |
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Hi Tracid,
in my eyes it should be:
}- \frac{(R2+R6)}{(R2+R6)+(R1+R5)}) "3$V=Uin\cdot ( \frac{R4}{(R3+R4)}- \frac{(R2+R6)}{(R2+R6)+(R1+R5)})")
ep20k
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