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koky
Joined: 12 May 2001
Posts: 156
Helped: 3
Location: Italy
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 30 Apr 2006 23:44 what (1<<LCRW) mean ? |
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I have found this source, but i don't understand why is used movlw (1<<LCRW)
what is the result ? why is not used a real value?
LCEN equ 1 ;rb1
LCRW equ 2; rb2
LCRS equ 3;rb3
tst_lcd_busy
movlw (1<<LCRW)
movwf PORTB
waitbusy
bsf PORTB,LCEN ; get hi-Nibble
rlf PORTB,w ; Busy-flag to Carry
bcf PORTB,LCEN
bsf PORTB,LCEN ; get lo-Nibble
bcf PORTB,LCEN
btfsc STATUS,C ;
goto waitbusy ;
return
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BeeBop
Joined: 19 Feb 2006
Posts: 161
Helped: 15
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01 May 2006 1:51 Re: what (1<<LCRW) mean ? |
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Hi Koky,
I may be wrong here, but, are you sure that is not (LCRW<<1) which means shift reg defined as LCRW (2) left one bit?
Regards,
Robert
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koky
Joined: 12 May 2001
Posts: 156
Helped: 3
Location: Italy
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01 May 2006 10:49 Re: what (1<<LCRW) mean ? |
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is : movlw (1<<LCRW)
and the software work, but i don't like use sw with strange assembler, i prefer rewrite it in more readable system
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dragan
Joined: 08 Apr 2001
Posts: 55
Helped: 3
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01 May 2006 11:59 Re: what (1<<LCRW) mean ? |
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THIS IS A PROGRAMED SHIFT.Shift 1 left for a value writed in LCRW.It is a common use in a IAR C compiler.
EG: /* Enable receiver and transmitter */
UCSR0B = (1<<RXEN)|(1<<TXEN);
/* Set frame format: 8data, 2stop bit */
UCSR0C = (1<<USBS)|(3<<UCSZ0);
}
Greetings
Dragan
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