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Jack// ani
Joined: 02 Dec 2004
Posts: 459
Helped: 23
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 03 Jan 2005 9:08 How is this calculated? |
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Q. If there are 1024*1280 pixels on a screen and each pixel can have around 16 million colors. Find the memory required for this?
Ans. 4MB
How is this calculated?
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papyaki
Joined: 13 Apr 2002
Posts: 564
Helped: 19
Location: A small village somewhere in Gaul
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| 03 Jan 2005 9:31 Re: How is this calculated? |
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Hi,
16 million colors per pixel means 24bits (2^24 = 16777216) or 3 bytes per pixel. A 1024 x 1280 pixels screen means 1310720 pixels.
The needed memory to store such a screen is 1310720 pixels x 3 bytes = 3932160 bytes, not far from 4Mbytes.
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bunalmis
Joined: 03 Jan 2003
Posts: 251
Helped: 4
Location: Turkey
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| 03 Jan 2005 9:45 Re: How is this calculated? |
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log(16e6)/log(2)=23.9 24 Bit need for 16 million color (3 Byte)
1024 * 1280 * 3 = 3932160 Byte = 3.75 Mbyte
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e_eja
Joined: 15 Nov 2003
Posts: 145
Helped: 4
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| 05 Jan 2005 12:20 Re: How is this calculated? |
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| if i have such deep colour scale now how we implement such that it can see on screen, crt , lcd and soon is there needed dac t implement
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pahol
Joined: 20 Jun 2003
Posts: 21
Helped: 1
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| 06 Jan 2005 9:22 Re: How is this calculated? |
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| The above is correct calculation. But please take care about real system implementation. If you implement on 32-bit system, and do you want high performance ? Because 32-bit system can work with 32-bit data for read/write. 3-byte (24-bit) operation may difficult and reduce performance. So you may use 4-byte (32-bit) for 1 pixel, That means 1024*1280*4 = 5 MB.
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bunalmis
Joined: 03 Jan 2003
Posts: 251
Helped: 4
Location: Turkey
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| 06 Jan 2005 9:33 Re: How is this calculated? |
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| Use 5Mbyt address space and 4Mbyte RAM.
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